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Emma Clarke, Maths, Year 1Due 18 Nov

Homework 3. Sequences

Let the sequence be defined by u0=2u_0 = 2 and un+1=0.5 un+3u_{n+1} = 0.5\,u_n + 3.

1. Compute the first terms.

u1=0.5×2+3=4u2=0.5×4+3=5u_1 = 0.5 \times 2 + 3 = 4 \qquad u_2 = 0.5 \times 4 + 3 = 5

2. Show that the following sequence is geometric:

vn=un−6v_n = u_n - 6vn+1=un+1−6=0.5 un−3=0.5 (un−6)=0.5 vn\begin{aligned} v_{n+1} &= u_{n+1} - 6 = 0.5\,u_n - 3 \\ &= 0.5\,(u_n - 6) = 0.5\,v_n \end{aligned}

So the sequence is geometric with common ratio q=0.5q = 0.5.

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